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affordable private tomcat private java print(" "); System.out.println(celsius); fahr = fahr + step; } // while loop ends here } // main ends here } //FahrToCelsius ends here I've made one further change to the Fahrenheit to Celsius program. All the integer constants in the program like have become and so on. If a constant number includes a decimal point, then the compiler assumes it's a double precision floating point number.
affordable private tomcat private java If it doesn't then the compiler assumes it's an integer. However when two numbers of different types such as integer and floating point are involved in a calculation , the compiler the number of the weaker type to the stronger type before doing the calculation. What makes one type of number stronger than another? It's the ability to represent a broader spectrum of numbers. Since a byte can only represent 256 numbers it's weaker than a short which can stand for 65,535 different numbers including all the numbers a byte can represent. Similarly an .
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