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frontpage Note how the rules for the two collators differ: String englishRules = ("< a,A < b,B < c,C < d,D < e,E < f,F " + "< g,G < h,H < i,I < j,J < k,K < l,L " + "< m,M < n,N < o,O < p,P < q,Q < r,R " + "< s,S < t,T < u,U < v,V < w,W < x,X " + "< y,Y < z,Z"); String smallnTilde = new String("\u00F1"); // ñ String capitalNTilde = new String("\u00D1"); // Ñ String traditionalSpanishRules = ("< a,A < b,B < c,C " + "< ch, cH, Ch, CH " + "< d,D < e,E < f,F " + "< g,G < h,H < i,I < j,J < k,K < l,L " + "< ll, lL, Ll, LL " + "< m,M < n,N " + "< " + smallnTilde + "," + capitalNTilde + " " + "< o,O < p,P < q,Q < r,R " + "< s,S < t,T < u,U < v,V < w,W < x,X " + "< y,Y < z,Z"); The following lines of code create the collators and invoke the sort routine: try { RuleBasedCollator enCollator = new RuleBasedCollator(englishRules); RuleBasedCollator spCollator = new RuleBasedCollator(traditionalSpanishRules); sortStrings(enCollator, words); printStrings(words); System.out.println(); sortStrings(spCollator, words); printStrings(words); } catch (ParseException pe) { System.out.println("Parse exception for rules"); } The sort routine, called , is generic.
frontpage It will sort any array of words according to the rules of any object: public static void sortStrings(Collator collator, String[] words) { String tmp; for (int i = 0; i < words.length; i++) { for (int j = i + 1; j < words.length; j++) { if (collator.compare(words[i], words[j]) > 0) { tmp = words[i]; words[i] = words[j]; words[j] = tmp; } } } } When sorted with the English collation rules, the array of words is as follows: chalina curioso llama luz Compare the preceding list with the following, which is sorted according to the traditional Spanish rules of collation: curioso chalina luz llama • • the Examples: FAQs. us your feedback.
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