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ssh2 hosting ssh2 hosting display="inline"; } the JDK Search the Tutorials Learning the Java Language Interfaces and Inheritance Inheritance > > If your method overrides one of its superclass's methods, you can invoke the overridden method through the use of the keyword to refer to a hidden field (although hiding fields is discouraged). Consider this class, : public class Superclass { public void printMethod() { System.out.println("Printed in Superclass."); } } Here is a subclass, called , that overrides : public class Subclass extends Superclass { public void printMethod() { //overrides printMethod in Superclass super.

ssh2 hosting printMethod(); System.out.println("Printed in Subclass"); } public static void main(String[] args) { Subclass s = new Subclass(); s.printMethod(); } } Within , the simple name refers to the one declared in , which overrides the one in inherited from , must use a qualified name, using prints the following: Printed in Superclass. Printed in Subclass The following example illustrates how to use the keyword to invoke a superclass's constructor.

ssh2 hosting Recall from the example that is a subclass of (subclass) constructor that calls the superclass constructor and then adds initialization code of its own: public MountainBike(int startHeight, int startCadence, int startSpeed, int startGear) { super(startCadence, startSpeed, startGear); seatHeight = startHeight; } Invocation of a superclass constructor must be the first line in the subclass constructor. The syntax for calling a superclass constructor is super(); --or-- super(parameter list); With , the superclass constructor with a matching parameter list is called. If a constructor does not explicitly invoke a superclass constructor, the Java compiler automatically inserts a call to the no-argument constructor of the superclass. If the super class does not have a no-argument constructor, you will get a compile-time error. have such a constructor, so if is the only superclass, there is no problem.

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